Question

Consider the following double-stranded DNA sequence that codes for a short polypeptide.
5'-A-T-G-T-G-G-C-C-A-C-T-A-T-A-A-T-C-A-3'
3'-T-A-C-A-C-C-G-G-T-G-A-T-A-T-T-A-C-T-5'
Which strand is the coding strand, and where is the N-terminal end of the resulting peptide located?

Answer 1

Answer:

Coding strand: 3'-T-A-C-A-C-C-G-G-T-G-A-T-A-T-T-A-C-T-5'

At the 5' end of mRNA strand transcribed from this DNA sequence

Explanation:

The coding strand is the strand that runs in the 3' to 5' direction. the mRNA strand to be produced is produced in the 5' to 3' direction on the coding strand. The N terminal end of the resulting peptide is located at the 5' end since mRNA codons resulting from transcription are read from 5' to 3' and they specify the order of amino acids in a protein which is from the N-terminus to C-terminus in a peptide chain.