Answer:
density of the metal silver = 6.6 [tex]\frac{g}{cm^{3} }[/tex]
Step-by-step explanation:
Piece of pure silver is in the shape a rectangular pyramid.
Volume of a rectangular pyramid = [tex]\frac{1}{3}(\text{Area of the rectangular base})\times (\text{height})[/tex]
= [tex]\frac{1}{3}(3\times 2)(1.5)[/tex]
= 3 cm³
Formula for the density is,
Density = [tex]\frac{\text{Mass}}{\text{Volume}}[/tex]
Density of silver = [tex]\frac{\text{Mass of the silver piece}}{\text{Volume of the silver piece}}[/tex]
= [tex]\frac{19.9}{3}[/tex]
= 6.63
≈ 6.6 [tex]\frac{g}{cm^{3} }[/tex]
Therefore, density of the metal silver = 6.6 [tex]\frac{g}{cm^{3} }[/tex]
