Question

Figure ABCD has vertices A(−3, 2), B(2, 2), C(2, −4), and D(−3, −2). What is the area of figure ABCD?

Answer 1

Answer:

30 units

Step-by-step explanation:

In order to find the side lengths, you can either draw it out, or imagine it in your head. I would recommend drawing it if you're unfamiliar to the topic.

So when you draw it out, you see that AB is the width of the rectangle, and BC is the length.

In order to calculate it, you'd have to keep in mind which direction each line goes. Since AB is horizontal, we would use the x coordinates to find the length. $x_{1}$-$x_{2}$ is the formula, where A is $x_{2}$, since it is farther left.

width = 2 - (-3)

w = 5

Now, you'd do the same thing, but with BC, and $y_{1}$-$y_{2}$. In this case, B is $y_{1}$, since it is further up.

length = 2 - (-4)

l = 6

Now, multiply them to find the area of a rectangle.

5 x 6 = 30

I hope this helps!