Question

A drawer contains 3 red paper clips 5 green paper clips and 4 blue paperclips one paper clip is taken from the drawer then replaced another paper clip is taken from the drawer what is the probability that the first paper clip is red and the second paper clip is blue?

Answer 1

Answer:

3/12 for red

4/12 for blue

Step-by-step explanation:

3 is red

5 is green

4 is blue

3 + 5 + 4 is 12 so it is out of 12 altogether

3/12 for red

4/12 for blue

Answer 2

The probability that the first paper clip is red and the second is blue is:

P = 1/12

How to get the probability?

The drawer has 3 red paper clips, 5 green paper clips and 4 blue paper clips, so a total of 3 + 5 + 4 = 12.

The probability of drawing a red one is equal to the quotient between the number of red paper clips and the total number of paper clips.

p = 3/12

Now we need to draw a blue one, because the first paper clip was replaced, now there are 12 in the drawer, then the probability is:

q = 4/12.

The joint probability is equal to the product of these two:

P = p*q = (3/12)*(4/12) = 1/12.

The probability that the first paper clip is red and the second is blue is:

P = 1/12

If you want to learn more about probability:

https://brainly.com/question/251701

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