Respuesta :
Answer:
Null hypothesis: [tex]\mu \leq 80[/tex]
Alternative hypothesis: [tex]\mu>80[/tex]
They calculate the following confidence interval: [tex]45.8 \leq \mu \leq 260.8[/tex]
And since the lower value of the confidence interval is lower than 80 we don't have enough evidence to conclude that the true mean is higher than 80 at the significance level given.
Step-by-step explanation:
Peevious concepts
[tex]\bar X[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
s represent the sample standard deviation
n=12 represent the sample size
[tex]\alpha=0.01[/tex] represent rhe significance level
Solution to the problem
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
For this case they want to test the following system of hypothesis:
Null hypothesis: [tex]\mu \leq 80[/tex]
Alternative hypothesis: [tex]\mu>80[/tex]
They calculate the following confidence interval: [tex]45.8 \leq \mu \leq 260.8[/tex]
And since the lower value of the confidence interval is lower than 80 we don't have enough evidence to conclude that the true mean is higher than 80 at the significance level given.
According to the hypothesis:
- A confidence level of 99% should be used.
- The lower bound of the confidence interval is below 80, which means that we cannot conclude that the population mean is greater than 80 sec.
We are using a level of significance of 0.01, thus, the confidence level is of 1 - 0.01 = 0.99 = 99%.
- We are testing if the population mean is greater than 80 sec.
- The confidence interval is between -45.8 sec and 260.8 sec.
- The lower bound is below 80, that it, it would be reasonable to find a mean time below 80 sec, thus, we cannot conclude that the population mean is greater than 80 sec.
A similar problem is given at https://brainly.com/question/24989605