Respuesta :
Answer:
[tex] p_v = P(z<-2.30) =0.0107[/tex]
Now we can decide based on the significance level [tex]\alpha[/tex]. If [tex]p_v <\alpha[/tex] we reject the null hypothesis and in other case we FAIL to reject the null hypothesis.
[tex]\alpha=0.05[/tex] we see that [tex] p_v< \alpha[/tex] so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 15
[tex]\alpha=0.01[/tex] we see that [tex] p_v> \alpha[/tex] so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15
[tex]\alpha=0.001[/tex] we see that [tex] p_v> \alpha[/tex] so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15
Explanation:
For this case they conduct the following system of hypothesis for the ture mean of interest:
Null hypothesis: [tex]\mu \leq 15[/tex]
Alternative hypothesis: [tex]\mu >15[/tex]
The statistic for this hypothesis is:
[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And on this case the value is given [tex] z = -2.30[/tex]
For this case in order to take a decision based on the significance level we need to calculate the p value first.
Since we have a lower tailed test the p value would be:
[tex] p_v = P(z<-2.30) =0.0107[/tex]
Now we can decide based on the significance level [tex]\alpha[/tex]. If [tex]p_v <\alpha[/tex] we reject the null hypothesis and in other case we FAIL to reject the null hypothesis.
[tex]\alpha=0.05[/tex] we see that [tex] p_v< \alpha[/tex] so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 15
[tex]\alpha=0.01[/tex] we see that [tex] p_v> \alpha[/tex] so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15
[tex]\alpha=0.001[/tex] we see that [tex] p_v> \alpha[/tex] so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15