Answer:
a = 1, b = -8
Step-by-step explanation:
you need complete the square to get a and b:
x^2+2x(+1)-7(-1)
by adding and subtracting 1 you aren’t changing the equation because 1-1=0
then u could simplify the equation to
(x+1)^2 - 8 to get a=1 and b=-8
The values of a and b such that x^2+2x-7=(x+a)^2+b is 1 and -8
The standard vertex form is expressed as (x+a)^2+b
Given the quadratic equation
x^2+2x-7
Using the completing the square method
x^2+2x + (2/2)²-7-(2/2)²
x^2 + 2x + 1 -7 - 1
(x+1)² - 8
Compare
a = 1 and b = -8
Hence the values of a and b such that x^2+2x-7=(x+a)^2+b is 1 and -8
Learn more on vertex form here; https://brainly.com/question/525947
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