Question

Find the value of in the triangle shown below

9, 7, and x around the triangle

Answer 1

Answer:

5.66 units

Step-by-step explanation:

A's per our discussion, x is a leg of right triangle.

Therefore, by Pythagoras theorem:

$x = \sqrt{ {9}^{2} - {7}^{2} } \\ = \sqrt{81 - 49} \\ = \sqrt{32}$

$x = \sqrt{ {16}^{2} - {12}^{2} } \\ = \sqrt{256 - 144} \\ = \sqrt{112}$