d = 12 cm
Step-by-step explanation:
Let small triangle and large triangles be given by [tex] \triangle _1\:\&\: \triangle _2\\[/tex]
Let the Marked angels of [tex] \triangle _1[/tex] be
[tex] \angle 1\: \&\: \angle 2\\[/tex]
Similarly Marked angels of [tex] \triangle _2[/tex] be [tex] \angle 3\: \&\: \angle 4\\[/tex]
[tex] \therefore \angle 1\cong \angle 3...(given) \\
\& \angle 2\cong \angle 4...(given) \\
\therefore \triangle _1\sim \triangle _2.. (By\: AA\:Postulate) \\
\therefore \frac{5}{15}=\frac{4}{d}..(By\: csst) \\
\therefore d =\frac{15\times 4}{5} \\
\therefore d =3\times 4\\
\huge \purple {\boxed {\therefore d =12\: cm}} \\[/tex]