Question

Write the equation of a line that is perpendicular to x=−6x, and that passes through the point (−1,−2)

Answer 1

Answer:

Step-by-step explanation:

y=-6x

slope=-6

slope of line ⊥ to given line=1/6

eq. of reqd. line is

y+2=-1/6 (x+1)

6y+12=-(x+1)

or

6y+12=-x-1

6y+x=-1-12

or 6y+x=-13

Answer 2

Answer:

y=-2

Step-by-step explanation:

Answer from Khanacademy