Answer:
[tex]36\sqrt{2}+30\sqrt{3}+10\sqrt{14}+8\sqrt{21}[/tex]
Step-by-step explanation:
Use the distributive property and the rules of roots.
[tex](2\sqrt{7}+3\sqrt{6})(5\sqrt{2}+4\sqrt{3}) = 10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=\boxed{36\sqrt{2}+30\sqrt{3}+10\sqrt{14}+8\sqrt{21}}[/tex]
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(a√b)(c√d) = (ac)√(bd)
√(a²b) = a√b
