Respuesta :
B2....b = 9
9(2) = 18.....unless that 2 is ^2...in that case B^2 = 9^2 = 81
ab + c.....a = 2, b = 3, c = 4
(2)(3) + 4 =
6 + 4 =
10
9(2) = 18.....unless that 2 is ^2...in that case B^2 = 9^2 = 81
ab + c.....a = 2, b = 3, c = 4
(2)(3) + 4 =
6 + 4 =
10
Answer:
1. The value of B² is 81.
2. The value of ab+c is 10.
Step-by-step explanation:
1.
We need to find the value of B².
The given information is
[tex]B=9[/tex]
Taking square on both the sides.
[tex]B^2=9^2[/tex]
[tex]B^2=81[/tex]
Therefore the value of B² is 81.
2.
Given information: a = 2, b = 3, and c = 4.
We need to find the value of ab+c.
Substitute a = 2, b = 3, and c = 4 in ab+c, to find the value of ab+c.
[tex]ab+c=2(3)+4[/tex]
[tex]ab+c=6+4[/tex]
[tex]ab+c=10[/tex]
Therefore the value of ab+c is 10.