On an algebra test, there are 7 students with As, 9 students with Bs, 11 students with Cs, 3 students with Ds, and 2 students with Fs. Find the probability that a randomly chosen student has D. Round to the nearest tenth of a percent.
students with D's / total students : 3 / (7 + 9 + 11 + 3 + 2) = 3 / 32 = 0.0937...to turn to a percent, multiply by 100 = 9.375....rounded = 9.4% <== ur probability
