Question

The area of a rectangle is 5x3+19x2+6x-18 with length x + 3. Using synthetic division, what is the width of the rectangle?

Answer 1

                 5  19    6  -18
        -3    
                    -15 -12   18

                 5    4   -6    0

Therefore, the width is 5x^2 + 4x - 6

Answer 2

The width of the rectangle using synthetic division is; 5x² + 4x - 6.

What is the width of the rectangle whose area is 5x³+19x²+6x-18?

From the task content; the width of the rectangle whose area and length are as given can be evaluated as follows;

Area = Length × width

Hence, width = Area/length.

Upon division by synthetic polynomial division or long division; the resulting expression for the width of the rectangle is; 5x² + 4x - 6.

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