Question

If h(t) = t^2/3 – 9 and j(t) = 3t + 5t^2/3,
what is h(t) – j(t)?
A) -4t^2/3-3t-9
B) 4t^2/3+3t+9
C) 3t+6t^4/3
D) -7t^7/3-9

Answer 1

Answer:

A

Step-by-step explanation:

$h(t)-j(t)=t^{\frac{2}{3}}-9-[3t+5t^{\frac{2}{3}}]\\\\=t^{\frac{2}{3}}-9-3t-5t^{\frac{2}{3}}\\\\=t^{\frac{2}{3}}-5t^{\frac{2}{3}}-3t-9\\\\=[1-5]*t^{\frac{2}{3}}-3t-9\\\\=-4t^{\frac{2}{3}}-3t-9$