Question

Two vectors have magnitudes of 1.8 m and 2.4 m. How are these vectors arranged, so their sum is 0.6 m?

Answer 1

Answer:

Perpendicular

Explanation:

write the angle between them as a

cosine theoreme

$0.6^{2} =1.8^{2} +2.4^{2}-2*1.8*2.4*cos(a)$

cos(a)=(3.24+5.76-0.6)/(2*1.8*2.4)

cos(a)=1

a=90°