Cindykayle
Cindykayle Cindykayle
  • 31-07-2016
  • Mathematics
contestada

solve for x
ln(8x-1)=2

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konrad509
konrad509 konrad509
  • 31-07-2016
[tex]D:8x-1\ \textgreater \ 0\\ D:8x\ \textgreater \ 1\\ D:x\ \textgreater \ \dfrac{1}{8}\\\\ \ln(8x-1)=2\\ e^2=8x-1\\ 8x=e^2+1\\ x=\dfrac{e^2+1}{8} [/tex]
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