Respuesta :

dalendrk
[tex]\dfrac{6r-7}{10}=\dfrac{r}{4}\ \ \ |cross\ multiply\\\\4(6r-7)=10r\\\\24r-28=10r\ \ \ |add\ 28\ to\ both\ sides\\\\24r=10r+28\ \ \ \ |subtract\ 10r\ from\ both\ sides\\\\14r=28\ \ \ |divide\ both\ sides\ by\ 14\\\\\boxed{r=2}[/tex]