Question

What is the molar mass of Mg(NO3)2? Explain how you calculated this value.

Answer 1

Atomic mass:

Mg = 24.0 u     N = 14.0 u    O = 16.0 u

Mg(NO3)2 = 24 + 14 x 2 + 16 x 6 => 148.0 g/mol

hope this helps!

Answer 2

Explanation:

Molar mass of a substance means the sum of atomic masses of each element present in the substance.

For example, in $Mg(NO_{3})_{2}$ there is one magnesium atom, two nitrogen atoms and six oxygen atoms.

Therefore, molar mass of $Mg(NO_{3})_{2}$ is calculated as follows.

  Molar mass = mass of Mg + mass of N atoms + mass of oxygen atoms

                      = 24.30 g/mol + (2 \times 14.00)g/mol + (6 \times 15.99)

                      = (24.30 + 28 + 95.94) g/mol

                      = 148.24 g/mol  

Thus, we can conclude that molar mass of $Mg(NO_{3})_{2}$ is 148.24 g/mol.