Respuesta :
Answer:
K = m g (A - A2)
Explanation:
In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential
Em = U₀ = m g A
For when the system is at an ele
Elongation A2 less than A, energy has two parts
Em = K + U₂
K = Em –U₂
We substitute
K = m g A - m gA2
K = m g (A - A2)
Answer:
ΔK.E = U0
Explanation:
Solution:-
- The spring constant = k
- The amount of distance displaced initially xo = A
- The potential energy stored at point xo = U0
- Considering the mass-spring system in isolation there are no external forces like viscous drag or friction acting, then we can safely apply the principle of conservation of energy.
- Which states:
ΔK.E = ΔP.E
Where, ΔK.E: The change in kinetic energy
ΔP.E: The change in potential energy
ΔK.E = U0 - Uf
Where, Uf : Final potential energy.
- The potential energy stored in the spring is given by:
U = 1/2*k*x^2
Where, x: The displacement of spring from mean position.
- Once the block has been released from displacement x = A/2 about mean position the block travels back to its mean position with displacement x = 0. So the final potential energy when the block has travelled a distance of A/2 is:
Uf = 1/2*k*0^2 = 0
So,
ΔK.E = U0 - Uf
ΔK.E = U0
