a sample of nitrogen gas is at a temperature of 50.0 *C and at a pressure of 2.00 atm. if the volume of the sample remains constant and the pressure increases to 3.20 atm, what is the new temperature of the nitrogen gas?

Respuesta :

Answer:

516.8 K or 243.8 C

Explanation:

- First figure out which gas law to use. In this case we need to use Gay-Lussac's law. This is P1/T1 = P2/T2.

- Next, we need to rearrange this to fit our problem. We should do...

T2 = T1P2/P1

- Now, we need to find our variables. For example...

T1 = 323 K

P1 = 2.00 atm

P2 = 3.20 atm

Next, fill in these numbers to fit our equation. For example...

T2 = 323 x 3.20 / 2.00 = 516.8 K

Note, you did not specify whether you wanted final answer in K or C, so I will put both. I suggest using K if nothing is stated for what they want.

- Hope this helps! If you need a more in-depth explanation please let me know.

Answer:244

Explanation:

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