Question

Suppose your company has decided that it needs to make certain busy servers 50% faster. processes in the workload spend 60% of their time using the cpu and 40% on i/o. in order to achieve an overall system speedup of 25%: how much faster does the disk need to be?

Answer 1

Answer:

The correct answer is 100% more faster.

Explanation:

According to the scenario, the computation of the given data are as follows:

Overall system speedup (S) = 25% + 100% = 125% = 1.25

Work done by Faster components (F) = 40% = 0.4

So, we can calculate the speed of disk (K) to run by using following formula:

S = $\frac{1}{(1 - F) + \frac{F}{K} }$

So, by putting the value, we get

1.25= $\frac{1}{(1 - 0.4) + \frac{0.4}{K} }$

After solving this, we get

K = 2

That means Disk has to twice its speed.

Hence, Disk needs to be 100% faster.