5.58 X [tex]10^{-25}[/tex] Litres is the volume, in liters, occupied by 0.015 molecules of oxygen at STP.
Explanation:
Data given:
molecules of oxygen = 0.015
number of moles of oxygen =?
temperature at STP = 273 K
Pressure at STP = 1 atm
volume = ?
R (gas constant) = 0.08201 L atm/mole K
to convert molecules to moles,
number of moles = [tex]\frac{molecules}{Avagadro's number}[/tex]
number of moles = 2.49 x [tex]10^{-26}[/tex]
Applying the ideal gas law since the oxygen is at STP,
PV = nRT
rearranging the equation:
V = [tex]\frac{nRT}{P}[/tex]
putting the values in the rearranged equation:
V = [tex]\frac{2.49 X10^{-26} X 0.08201 X 273}{1}[/tex]
V = 5.58 X [tex]10^{-25}[/tex] Litres.
