The answer for the following problems is mentioned below.
Explanation:
Mole:
The mass of a substance containing the same number of fundamental units as there are atoms in exactly 12.000 g of [tex]C^{12}[/tex].
Given:
volume (v) = 4.7 litres
Volume of argon at STP conditions = 22.4 litres
To find:
volume of argon at STP conditions
We know;
n = [tex]\frac{v}{V}[/tex]
where;
n represents the no of moles
v represents the volume of the argon
V represents the volume of argon at STP
volume of the argon at STP conditions is 22.4 litres
So;
n = [tex]\frac{4.7}{22.4}[/tex]
n = 0.20 moles
Therefore the number of moles present in Argon is 0.20 moles.