Question

F=9/5C+32, solve for C

Answer 1

$\dfrac{9}{5}C+32=F\ \ \ \ |subtract\ 32\ from\ both\ sides\\\\\dfrac{9}{5}C=F-32\ \ \ \ |multiply\ both\ sides\ by\ \dfrac{5}{9}\\\\\boxed{C=\frac{5}{9}(F-32)}$

Answer 2

F=9/5C+32
F-32=9/5C
9/5C=F-32
9C=5(F-32)
C=$\frac{5(F-32)}{9}$