Answer:
The value of the test statistic = 6.03
Step-by-step explanation:
The test statistics for a proportion of the population is the z calculated as follows;
[tex]z=\frac{\hat{p}-p}{\sqrt{\frac{pq}{n}}}[/tex]
Where:
[tex]\hat{p}[/tex] = 0.64
From the rule of large numbers we have, the proportion of adults who will erase their information online will tend towards 1/2 or 0.5 therefore, we have
p = 0.5 as the test
q = 1 - p = 1 - 0.5 = 0.5
n = Sample size = 464
Therefore, z is given by;
[tex]z=\frac{0.64-0.5}{\sqrt{\frac{0.5 \times 0.5}{464}}}[/tex]
= 6.03
The value of the test statistic = 6.03.
