Step-by-step explanation:
The total number of students = 100
Let A represents calculus and B represents French
The no of students taking calculus = 32
The no of students taking French = 29
The no of students taking calculus and french = 13
the probability that the student is taking Calculus or French = ?
P (AUB) = P(A) + P(B) - P(A∩B)
= [tex]\frac{32}{100}[/tex] + [tex]\frac{29}{100}[/tex] - [tex]\frac{13}{100}[/tex]
= [tex]\frac{48}{100}[/tex]
Reducing to lowest fraction, it becomes [tex]\frac{12}{25}[/tex]
The probability that the student is taking Calculus or French = [tex]\frac{12}{25}[/tex]