Respuesta :
Answer:
a is the correct answer
Explanation:
i just did this question and it said a was right
The number of moles of aluminum sulfate produced from the 5.8 moles of aluminum hydroxide and excess sulfuric acid is 2.9 moles.
The balanced chemical equation can be given as:
2 Al(OH)₃ + 3 H₂SO₄ [tex]\rightarrow[/tex] Al₂(SO₄)₃ + 6 H₂O
In the above reaction, the stoichiometry of the amounts of each compound participating in the reaction is:
Al(OH)₃ - 2 moles
H₂SO₄ - 3 moles
Al₂(SO₄)₃ - 1 mole
H₂O - 6 moles
From the above observation, it can be assumed that for every 2 moles of aluminum hydroxide produce 1 mole of aluminum sulfate.
Then, the number of moles produced by 5.8 moles of aluminum hydroxide is x.
[tex]\text{moles of Al}_{2} (\text{SO}_{4} ){3} =\dfrac{\text{5.8moles of Al(OH)}_{3} \times \text {1 mole of Al}_{2} (\text {SO}_{4} ){3}}{\text {2moles of Al(OH)}_{3}}[/tex]
Thus, 2.9 moles of aluminum hydroxide will be produced from the 5.8 moles of aluminum hydroxide.
To know more about moles, refer to the following link:
https://brainly.com/question/20486415
