Question

WILL GIVE BRAINLIEST
A bicycle tire has a diameter of 26 inches. How far does it travel (to the nearest tenth) in 10 rotations?

Answer 1

Answer:

816.8

Step-by-step explanation:

For each rotation of the tire, the wheel axle moves forward by a distance equal to the circumference of the tire.

Here, that circumference is C = pi*d, where d is the wheel diameter:

C = pi(26 in) = 26 pi inches.

The distance covered in 10 rotations of the wheel is thus 10(26 pi inches) = 260 pi inches. To the nearest tenth, that's 816.8 inches.