Respuesta :

Let X = 3:

3x/2 + 7/2 = 2^x.
3*3/2 + 7/2 = 2^3.
9/2 + 7/2 = 8.
16/2 = 8.
8 = 8.

So X = 3 is the answer my friend!

Answer:

[tex]x= \frac{7}{4},-1[/tex]  is the required solution.

Step-by-step explanation:

We have been given the equation:

[tex]\frac{3}{2}\cdot \frac{x+7}{2}=x^2[/tex]

We will solve for x to get the solution of the equation

After first step of simplification we get:

[tex]\frac{3x}{2}+\frac{7}{2}=2x^2[/tex]

Now, distribute the parenthesis on left hand side of the equation:

[tex]3x+7=4x^2[/tex]

[tex]4x^2-3x-7=0[/tex]

We will solve the above quadratic equation by discriminant rule

[tex]x=\frac{-b\pm\sqrt{D}}{2a}[/tex]

Where, [tex]D=b^2-4ac[/tex]

We will compare the equation with general quadratic equation:

[tex]ax^2+bx+c=0[/tex]

Here, a=4,b= -3 and c=-7 on substituting the values we get:

[tex]D=(-3)^2-4(4)(-7)[/tex]

[tex]D=9+112=121[/tex]

Now for x

[tex]x=\frac{-(-3)\pm\sqrt{121}}{2\cdot 4}[/tex]

[tex]x= \frac{3\pm\11}{8}[/tex]

[tex]\Rightarrow \frac{14}{8},\frac{-8}{8}[/tex]

[tex]\Rightarrow \frac{7}{4},-1[/tex]

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