Answer:
[tex]\frac{1}{6}[/tex]
Step-by-step explanation:
The factors of 15 are numbers that can divide even through 15 without any remainders.
These numbers are 1, 3, 5 and 15;
When we roll two fair dice once, there are about 36 possible out comes and this is the sample space of rolling this fair dice.
1 2 3 4 5 6
1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)
6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
The total that will give a factor of 15;
(1, 2) (2, 3) (1, 4) (2, 1) (3, 2) (4, 1)
Out of the 36 possible outcomes, we have 6 whose sum will give a factor of 15;
Probability of this = [tex]\frac{6}{36}[/tex] = [tex]\frac{1}{6}[/tex]
