Complete the steps to find the area of the trapezoid.
Area of rectangle = square units
Area of triangle 1 = square units
Area of triangle 2 = square units
Area of triangle 3 = square units
Area of trapezoid = square units

Complete the steps to find the area of the trapezoid Area of rectangle square units Area of triangle 1 square units Area of triangle 2 square units Area of tria class=

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Answer:

Area of rectangle: 256

Area of triangle 1: 24

Area of triangle 2: 16

Area of triangle 3: 96

Area of trapezoid: 120

Step-by-step explanation:

I just did the question on the thing so Ik I'm right.

-The graph measures by twos. To get the area of the rectangle get the base times height of it. That would be 16x16=256.

-Get base (8) times height (6) of triangle 1 then divide by 2, remember to count the squares by 2 for finding all areas. The formula would be 1/2(b)(h) because dividing by 2 is the same as multiplying times 1/2. Plug it in and     (8)(6)=48 then divide by 2 which equals 24.

-Same formula for triangle 2. Plug it in and (8)(4)=32 and divide by 2 and it equals 16.

-Same formula for triangle 3. Plugged in is (12)(16)=192 divide by 2 and it equals 96.

-To find the area of the trapezoid get your rectangle area (256) and subtract all the triangle areas. So 256 - 6 - 16 - 96 = 120.

The area of the given shapes are required.

256 square units

24 square units

16 square units

96 square units

120 square units

Area of the rectangle

[tex]A_r=(20-4)\times(20-4)\\\Rightarrow A_r=256\ \text{square units}[/tex]

The area of a right triangle is given by

[tex]\dfrac{1}{2}bh[/tex]

where

b = Base

h = Height

Every triangle here is a right triangle.

Triangle 1

[tex]b=20-14=6\ \text{units}[/tex]

[tex]h=12-4=8\ \text{units}[/tex]

[tex]A_1=\dfrac{1}{2}\times 6\times 8\\\Rightarrow A_1=24\ \text{square units}[/tex]

Triangle 2

[tex]b=20-16=4\ \text{units}[/tex]

[tex]h=20-12=8\ \text{units}[/tex]

[tex]A_2=\dfrac{1}{2}\times 4\times 8\\\Rightarrow A_2=16\ \text{square units}[/tex]

Triangle 3

[tex]b=20-4=16\ \text{units}[/tex]

[tex]h=16-4=12\ \text{units}[/tex]

[tex]A_3=\dfrac{1}{2}\times 16\times 12\\\Rightarrow A_3=96\ \text{square units}[/tex]

Area of trapezoid is Area of the rectangle minus Area of all the triangles.

[tex]A=A_r-(A_1+A_2+A_3)\\\Rightarrow A=256-(24+16+96)\\\Rightarrow A=120\ \text{square units}[/tex]

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