The area of the given shapes are required.
256 square units
24 square units
16 square units
96 square units
120 square units
Area of the rectangle
[tex]A_r=(20-4)\times(20-4)\\\Rightarrow A_r=256\ \text{square units}[/tex]
The area of a right triangle is given by
[tex]\dfrac{1}{2}bh[/tex]
where
b = Base
h = Height
Every triangle here is a right triangle.
Triangle 1
[tex]b=20-14=6\ \text{units}[/tex]
[tex]h=12-4=8\ \text{units}[/tex]
[tex]A_1=\dfrac{1}{2}\times 6\times 8\\\Rightarrow A_1=24\ \text{square units}[/tex]
Triangle 2
[tex]b=20-16=4\ \text{units}[/tex]
[tex]h=20-12=8\ \text{units}[/tex]
[tex]A_2=\dfrac{1}{2}\times 4\times 8\\\Rightarrow A_2=16\ \text{square units}[/tex]
Triangle 3
[tex]b=20-4=16\ \text{units}[/tex]
[tex]h=16-4=12\ \text{units}[/tex]
[tex]A_3=\dfrac{1}{2}\times 16\times 12\\\Rightarrow A_3=96\ \text{square units}[/tex]
Area of trapezoid is Area of the rectangle minus Area of all the triangles.
[tex]A=A_r-(A_1+A_2+A_3)\\\Rightarrow A=256-(24+16+96)\\\Rightarrow A=120\ \text{square units}[/tex]
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