Question

Parallel lines e and f are cut by transversal b.

Horizontal and parallel lines e and f are cut by transversal b. At the intersection of lines b and e, the uppercase right angle is (2 x + 18) degrees. At the intersection of lines b and f, the top right angle is (4 x minus 14) degrees and the bottom right angle is y degrees.

What is the value of y?

16
50
130
164

Answer 1

Answer:

130

Step-by-step explanation:

e // f

2x + 18 = 4x - 14

2x = 32

x = 16

y = 180 - (4x - 14) = 180 - (64 - 14) = 130

Answer 2

Using the congruency of the top-right angles, it is found that the value of y is of 130.

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• When two parallel lines are cut by a transversal, the top-right angles are congruent, that is, they have the same measure.
• In this question, their measures are of (2x + 18)º and (4x - 14)º. Thus, with this, we can find x:

$4x - 14 = 2x + 18$

$2x = 32$

$x = \frac{32}{2}$

$x = 16$;

• Thus, the measure of the top right angles is given by, in degrees: $4x - 14 = 4(16) - 14 = 64 - 14 = 50$

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• The top-right and the bottom-right angles are supplementary, that is, the sum of their measures is 180º.
• The measure of the top-right angle is of 50º.
• The measure of the bottom-right angle is of y.

Thus:

$y + 50 = 180$

$y = 130$

The value of y is of 130.

A similar problem is given at https://brainly.com/question/16368729