Respuesta :
Answer:
Given the system of equation:
2x+y = 1 .....[1]
4x+2y = -2 .....[2]
We can write equation [1] as:
y = 1-2x
Substitute the value of y in [2] we have;
[tex]4x+2(1-2x) = -2[/tex]
Using distributive property, [tex]a \cdot(b+c) = a\cdot b+ a\cdot c[/tex]
then;
[tex]4x+2-4x = -2[/tex]
Combine like terms;
[tex]2= -2[/tex] False.
Therefore, there is no solution and x = ∅
The system of equations has [tex]\boxed{\text{\bf no solution}}[/tex].
Further explanation:
Given information:
The system of equation is as follows:
[tex]\boxed{\begin{aligned}2x+y&=1\\4x+2y&=-2\end{aligned}}[/tex]
Calculation:
The given equations are as follows:
[tex]2x+y=1[/tex] .....(1)
[tex]4x+2y=-2[/tex] …… (2)
Simplify equation (1) as follows:
[tex]\begin{aligned}2x+y&=1\\y&=1-2x\end{aligned}[/tex]
Substitute [tex]1-2x[/tex] in place of [tex]y[/tex] in equation (2) as follows:
[tex]4x+2(1-2x)=-2[/tex]
Use distributive property to expand the brackets as follows:
[tex]\begin{aligned}4x+2(1-2x)&=-2\\4x+2-4x&=-2\\2&\neq -2\end{aligned}[/tex]
The above result obtained is not possible, then any value of [tex]x[/tex] and [tex]y[/tex] will not satisfy the given equations.
This implies that the system is inconsistent.
Therefore, there is [tex]\boxed{\text{\bf no solution}}[/tex] to the given system of equations.
Graph:
To graph the line, first make a table of set of values. Then plot the points from the table and join the points to obtain the graph.
Equation (1) is expressed as follows:
[tex]y=1-2x[/tex] …… (3)
Substitute [tex]0[/tex] for [tex]x[/tex] in above equation to obtain the corresponding value of [tex]y[/tex] as,
[tex]\begin{aligned}y&=1-(2\times 0)\\y&=1\end{aligned}[/tex]
Substitute [tex]3[/tex] for [tex]x[/tex] in equation (3) to obtain the corresponding value of [tex]y[/tex] as,
[tex]\begin{aligned}y&=1-(3\times 3)\\&=1-9\\&=-8\end{aligned}[/tex]
Now, make the table with the set of values as shown in Table 1.
Equation (2) is expressed as follows:
[tex]\begin{aligned}2y&=-2-4x\\2y&=2(-1-2x)\\y&=-1-2x\end{aligned}[/tex] Substitute [tex]0[/tex] for [tex]x[/tex] in equation (4) to obtain the corresponding value of [tex]y[/tex] as,
[tex]y=-1[/tex]
Substitute [tex]2[/tex] for [tex]x[/tex] in equation (4) to obtain the corresponding value of [tex]y[/tex] as,
[tex]\begin{aligned}y&=-1-(2\times 2)\\&=-1-4\\&=-5\end{aligned}[/tex]
Now, make the table with the set of values as shown in Table 2.
Now, plot the points and join them with a straight line to obtain the graph of the lines.
The graph of the lines is shown in Figure 1.
In Figure 1, the equation of blue line is [tex]4x+2y=-2[/tex] and the equation of red line is [tex]2x+y=1[/tex].
And also it is seen that both the lines are parallel to each other.
Therefore, the system of equations has [tex]\boxed{\text{\bf no solution}}[/tex].
Learn more:
1. A problem on graph https: //brainly.com/question/2491745
2. A problem on linear equation: https://brainly.com/question/1473992
Answer details:
Grade: Middle school
Subject: Mathematics
Chapter: Linear equations
Keywords: Solve, system, equations, substitution, solution, 2x+y=1, 4x+2y=-2, graph, linear, parallel, no solution, inconsistent, distributive property, linear equation.

