Respuesta :
7 moles of BaBr₂ produces 14 moles of KBr.
Explanation:
Given reaction is
BaBr₂ + K₂SO₄ → KBr + BaSO₄
It can be balanced by putting 2 in front of KBr as,
BaBr₂ + K₂SO₄ → 2 KBr + BaSO₄
From the above balanced equation, it was found that, 1 mole of Barium bromide required to produce 2 moles of KBr.
Now the molar ratio of BaBr₂ to KBr is written as 1 : 2.
In the same way, the molar ratio for 7 moles of BaBr₂, can be written as 7:14.
So 7 moles of BaBr₂ produces 14 moles of KBr.
The moles of KBr formed has been 14 mol.
The balanced chemical equation for the reaction has been:
[tex]\rm BaBr_2\;+\;K_2SO_4\;\rightarrow\;2\;KBr\;+\;BaSO_4[/tex]
From the balanced chemical equation, the coefficient has been describing the moles of reactants and products formed.
The balanced chemical equation has been given as:
[tex]\rm 1\;mol\;BaBr_2=2\;mol\;KBr[/tex]
The moles of KBr formed by 7 moles of Barium bromide has been as:
[tex]\rm 1\;mol\;BaBr_2=2\;mol\;KBr\\7 \;mol\;BaBr_2=2\;\times\;7 \;mol\;KBr\\7 \;mol\;BaBr_2=14 \;mol\;KBr\\[/tex]
The moles of KBr formed has been 14 mol.
For more information about moles, refer to the link:
https://brainly.com/question/20674302
