Question

what is the value of x?
(geometry question)

Answer 1

Given:

The interior angles of the triangle are 44°, 3t - 45° and x - 15°

The exterior angle of the triangle is 4t - 29°

We need to determine the value of x.

Value of t:

The value of t can be determined using the exterior angle theorem.

Applying the theorem, we have;

$44+3t - 45=4t-29$

         $3t - 1=4t-29$

        $-t - 1=-29$

              $-t=-28$

                $t=28$

Thus, the value of t is 28.

Value of x:

The exterior angle 4t -29 and the interior angle x - 15 are linear pairs.

Since, linear pairs add up to 180°, we have;

$4t-29+x-15=180$

Substituting t = 28, we get;

$4(28)-29+x-15=180$

  $112-29+x-15=180$

                   $x+68=180$

                           $x=112$

Thus, the value of x is 112.