Respuesta :
a. Exactly two people will agree
n = 5, p = 0.40
P(2 people) = 5!/((5–2)!2!)•(0.4)^2(1– 0.4)^(5–2)
= [5!/(3!2!)]•(0.4)^2(0.6)^3
= 0.346
b. At most three people will agree.
P(X) = 0.078 + 0.259 + 0.346 + 0.230
= 0.913
c. At least two people will agree.
X= 2, 3, 4,
or
5 people P(X) = 0.346 + 0.230 + 0.077 + 0.01
= 0.663
d. Fewer than three people will agree.
X= 0, 1, or 2
people P(X) = 0.078 + 0.259 + 0.346
= 0.683
n = 5, p = 0.40
P(2 people) = 5!/((5–2)!2!)•(0.4)^2(1– 0.4)^(5–2)
= [5!/(3!2!)]•(0.4)^2(0.6)^3
= 0.346
b. At most three people will agree.
P(X) = 0.078 + 0.259 + 0.346 + 0.230
= 0.913
c. At least two people will agree.
X= 2, 3, 4,
or
5 people P(X) = 0.346 + 0.230 + 0.077 + 0.01
= 0.663
d. Fewer than three people will agree.
X= 0, 1, or 2
people P(X) = 0.078 + 0.259 + 0.346
= 0.683
The probabilities for the people should be
a. 0.346.
b. 0.913.
c. 0.663.
d. 0.683.
Calculation of the probabilities:
Since 40% of Americans do not think having a college education
So,
a. Exactly two people will agree
n = 5, p = 0.40
P(2 people) = 5!/((5–2)!2!)•(0.4)^2(1– 0.4)^(5–2)
= [5!/(3!2!)]•(0.4)^2(0.6)^3
= 0.346
b. At most three people will agree.
P(X) = 0.078 + 0.259 + 0.346 + 0.230
= 0.913
c. At least two people will agree.
X= 2, 3, 4,
or
5 people P(X) = 0.346 + 0.230 + 0.077 + 0.01
= 0.663
d. Fewer than three people will agree.
X= 0, 1, or 2
people P(X) = 0.078 + 0.259 + 0.346
= 0.683
learn more about probabilities here: https://brainly.com/question/24710931