Question

the half life of radon is 3.80days what would be its decay constant

Answer 1

Half life formula is, 0.5=ek∗t where, k=decay constant t=time substitute time, we get 0.5=ek∗3.80 taking natural logarithm on both sides, we get, ln(0.5)=k∗3.80 or, ln(0.5)/3.80=k k=0.182(ANSWER)