Question

These equations represent the results of dissolving different substances in water. For each dissolution,
the results of a conductivity test are given. The conductivity test involves placing wires connected to a
battery and a light bulb into the solution. If the solution is able to conduct electricity, the bulb will light.
Identify each substance as a strong electrolyte, weak electrolyte, or nonelectrolyte.
(NH4)2SO4(s) → 2NH4+ (aq) + S04 (aq)
light bulb glows brightly:
CuSO4(s) → Cu2+(aq) + SO42-(aq)
light bulb glows brightly:
HF(g) + H2O(1) → H30+ (aq) + F→ (aq)
light bulb glows faintly:
C3H6O(1) → C3H60(aq)
light bulb does not glow:

Answer 1

Answer:

Strong electrolyte

Strong electrolyte

Weak electrolyte

Non electrolyte

Answer 2

Considering the equations, the nature of the electrolyte in each case is as follows;

1) Strong electrolyte

2) Strong electrolyte

3) Weak electrolyte

4) Non electrolyte

What is an electrolyte?

An electrolyte is a solution that is able to conduct electricity because of the presence of ions in the solution.

We shall now identify whether or not each solution is a strong electrolyte/ weak electrolyte or non electrolyte;

1) Strong electrolyte

2) Strong electrolyte

3) Weak electrolyte

4) Non electrolyte

Learn more about electrolytes:https://brainly.com/question/14566383

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