Question

A baboon pushes a 3.1 kg stone with 150 j of kinetic energy.
What is the stone’s speed?

Answer 1

The speed of the stone is 9.8 m/s

Explanation:

Given data,

Mass - 3 kg    K.E 150-J

We have to find the speed of the stone

We have the formula

K.E =1/2 m× v ²

Rewrite the equation as

v= √ 2×K.E/m

v= √2 ×150/ 3.1

v=9.83 m/s

The speed of the stone is 9.8 m/s