Respuesta :

 Summation notation to write the series 49 + 54 + 59 +... for 14 terms is attached .
I hope that will help.

Ver imagen Hussain514

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by:  [tex]a_n = a+(n-1)d[/tex] where a is the first term , n is the number of term and d is the common difference.

Given the series: [tex]49 + 54 + 59+ ......[/tex]

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

[tex]a_n = a+(n-1)d[/tex]

[tex]a_n = 49+(n-1)5[/tex]

[tex]a_n =49+5n -5[/tex] = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol [tex]'\sum'[/tex]

The series for 14th terms is given by;

[tex]\sum_{n=1}^{14}(5n +44)[/tex]


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