Respuesta :
Summation notation to write the series 49 + 54 + 59 +... for 14 terms is attached .
I hope that will help.
I hope that will help.

Answer:
Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.
it is given by: [tex]a_n = a+(n-1)d[/tex] where a is the first term , n is the number of term and d is the common difference.
Given the series: [tex]49 + 54 + 59+ ......[/tex]
here, Common difference(d) = 5
First term(a) = 49
by definition we have;
For nth term
[tex]a_n = a+(n-1)d[/tex]
[tex]a_n = 49+(n-1)5[/tex]
[tex]a_n =49+5n -5[/tex] = 5n + 44
To write the series using summation notation for 14 terms
Summation symbol [tex]'\sum'[/tex]
The series for 14th terms is given by;
[tex]\sum_{n=1}^{14}(5n +44)[/tex]