The pH of this solution is 13.
We can solve this question knowing that a hydroxide as MOH, dissociates in water as follows:
MOH(aq) ⇄ M⁺(aq) + OH⁻(aq)
Based on the reaction, 1 mole of MOH produces 1 mole of OH⁻
If 10% of the 1M MOH dissociates, a 0,1M of M⁺ and a 0.1M of OH⁻ are produced.
Now, with molarity of OH⁻ we can find pOH (pOH = -log[OH⁻]) and pH (pH = 14-pOH) as follows:
pOH:
pOH = -log [OH⁻] = -log [0.1] =1
And pH:
pH:
pH = 14 - pOH
pH = 13
You can learn more about pH and pOH in:
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