Question

Sophia factored 81y^6 as (9y^3)(9y^2) Ahmed factored 81y^6 as (3y^6)(27y) Which of them factored 81y^6 correctly?

Answer 1

To find if either of them are correct just multiply each of them:

(9y^3)(9y^2)= (9)(9)(y^3)(y^2)

=81y^5

Sophia is incorrect.

(3y^6)(27y)=(3)(27)(y^6)(y)

=81y^7

Ahmed isn't correct either!