We have been given a system of equations. [tex]f(x)=x-4[/tex] and [tex]g(x)=x^2-10[/tex]. We are asked to find the solution of the equation [tex]f(x)=g(x)[/tex] by sketching the functions.
We can see that f(x) is a linear function in slope-intercept form. The slope of f(x) is 1 and y-intercept at point [tex](0,-4)[/tex].
We can also see that g(x) is a quadratic function. The function g(x) is an upward opening parabola, whose vertex is at point [tex](0,-10)[/tex].
Upon graphing both equations, we will get our required graph as shown in the attachment.
The solution of [tex]f(x)=g(x)[/tex] will be the x-coordinates of points, where both functions will intersect.
We can see that both functions are intersecting at [tex]x=-2\text{ and }3[/tex], therefore, [tex]-2\text{ and }3[/tex] are the solutions of [tex]f(x)=g(x)[/tex] and option B is the correct choice.