Question

what is the magnitude of 6 2i?

Answer 1

Hello,

z=6+2i
||z||=√(6²+2²)=√40=2√10

Answer 2

Answer:

$2\sqrt{10}$

Step-by-step explanation:

Given equation  

$6 + 2i$

Where "i" signifies an imaginary number

We know that

$a+bi = \sqrt{(a^2 + (-b)^2)}$-------Eq (A)

Here ,  

a $= 6$

b$= -2$

Substituting the given values in equation (A), we get -

$6+2i\\= \sqrt{(6^2+(-2)^2} \\= \sqrt{(36+4)}\\ = \sqrt{40}\\ = \sqrt{4*10} \\= 2\sqrt{10}$

Hence, the values of equation is  $2\sqrt{10}$