Answer:
crosses 2 and 3.
Explanation:
Crosses 2 and 3 are likely to have at least one parent with genotype RR.
Since R has been established to be dominant over r, in order for the outcome of a cross to yield 100% red-winged offspring as obtained in crosses 2 and 3, at least one of the parents must have RR as genotype. The other parent can have rr, RR or Rr genotype.
RR x rr
Progeny: all Rr genotype with red-winged phenotype
RR x RR
Progeny: all RR, red-winged
RR x Rr
progeny: RR, Rr, RR, Rr. All red-winged in appearance.
In order to produce clear wings (rr) as in cross 1, at least one r allele must be present in the genotype of the two parents, there cannot be RR genotype.
Hence, only crosses 2 and 3 requires at least one parent with RR genotype.