Question

What is the final pressure of a 9.6 Liters system initially at 14.45 atm and 127.9 degrees celsius that is compressed to a final volume of 17.5l at 35 degrees celsius

Answer 1

Answer:

$p_2=6.1atm$

Explanation:

Hello,

In this case, when the pressure-temperature-volume behavior is analyzed in ideal gases, the following equation is employed:

$\frac{p_1V_1}{T_1} =\frac{p_2V_2}{T_2}$

Whereas the subscript 1 accounts for the initial state and the subscript 2 for the final state. Therefore, solving for the final pressure we obtain:

$p_2=\frac{p_1V_1T_2}{V_2T_1} =\frac{14.45atm*9.6L*(35+273.15)K}{17.5L*(127.9+273.15)K} \\\\p_2=6.1atm$

Best regards.