Respuesta :

DeanR

We have

A = 100(0.5)^t

where t is in half-life units, t=1 is 35 days after t=0.

The daily decay rate is the decay after 1 day, which corresponds to t=1/35

0.5^(1/35) = 0.98039...

Answer: 98.0%  first choice

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