Question

What is the molality of a solution containing 100 grams of glucose (C6H12O6, molar mass = 180 g/mol) dissolved in 2.5 kg of water?

Group of answer choices

40 m

0.22 m

72 m

7200 m

Answer 1

Answer:

The answer to your question is molality = 0.22

Explanation:

Data

molality = ?

mass of glucose = 100 g

molar mass of glucose = 180 g

mass of water = 2.5 kg

Process

1.- Calculate the moles of glucose using proportions

                180 g ------------------ 1 mol

                100 g ------------------  x

                   x = (100 x 1) / 180

                   x = 100 / 180

                   x = 0.56 moles

2.- Calculate the molality

Formula

molality = moles / mass of solvent

- Substitution

molality = 0.56 / 2.5

- Simplification

molality = 0.22