The volume required to titrate 10.8M HCl with 100.0 mL of 3.00M acid is 27.78mL. Details about volume can be found below.
How to calculate volume?
The volume of a substance can be calculated using the following formula:
C1V1 = C2V2
Where;
- C1 = initial concentration
- C2 = final concentration
- V1 = initial volume
- V2 = final volume
According to this question, 10.8M HCl are required to make 100.0 mL of 3.00M acid. The volume of HCl required is as follows:
10.8 × V1 = 100 × 3
10.8V1 = 300
V1 = 27.78mL
Therefore, the volume required to titrate 10.8M HCl with 100.0 mL of 3.00M acid is 27.78mL.
Learn more about volume at: https://brainly.com/question/1578538
